Slot Machine Code C++
I am trying to write a simple slot machine program that will return three numbers as the slot icons using a loop. I can get the first part just fine (I think). But I am stuck at converting my icons to intergers or character that I can compare to see if it is a winner or not. Here so far:
Slot Machine Code C++ Bee Swarm Simulator
I have tried to add the following to my loop without success:
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if (c 1 )
Win1 = Win;
if (c 2)
Win2 = Win;
if (c 3)
Win3 = Win;
I was then going to usr the integers Win1, Win2 etc to make my comparisons but it doesn't work. I feel like I am missing something very simple.
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- commentLatest PostLatest Postby Sky Diploma
Most of the time, that many parameters means your design needs work. Since the first five variables are slots, you can easily use an array instead. It's also a good idea to use parameter names even in your prototypes. Even though they aren't required, their presence does make understanding the code easier. Of course, this assumes well chosen names.
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I am trying to write a simple slot machine program that will return three numbers as the slot icons using a loop. I can get the first part just fine (I think). But I am stuck at converting my icons to intergers or character that I can compare to …
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I am trying to write a simple slot machine program that will return three numbers as the slot icons using a loop. I can get the first part just fine (I think). But I am stuck at converting my icons to intergers or character that I can compare to see if it is a winner or not. Here so far:
// slot machine
#include<iostream>
#include<cstdlib>
#include<ctime>
Slot Machine Code In C++
using namespace std;
int main()
{
int Win1 = 0, Win2 = 0, Win3 = 0;
srand (time(0)); // seed random number generator based on time
/* creating a counter and loop to generate three
random numbers */
int c; // create a counter
for (c = 0; c < 3; c++) //initialize, test and update the counter
{
int random = rand(); // generate random number
int Win = (random % 3) + 1; // constrain random number between 1 and 3
cout << Win << ' ';
}
return 0;
}
I have tried to add the following to my loop without success:
if (c 1 )
Win1 = Win;
if (c 2)
Win2 = Win;
if (c 3)
Win3 = Win;
I was then going to usr the integers Win1, Win2 etc to make my comparisons but it doesn't work. I feel like I am missing something very simple.
Code tags please:
[code]
// paste code here
[/code]
So you win if you get 1 - 2 -3, otherwise you lose? There is more than one way to do this. One way would be to set up a boolean variable called winner
and initialize it to true. Each time through the loop, check to see if the winning number come up. If not, flag winner to false. Any incorrect number that comes up causes winner
to be false, so you'll need to initialize winner
to true before the loop starts, generate your random number inside the loop, then have an if-statement inside the loop that compares that random number to the number needed to win and if they aren't the same, make winner
false. Finally, after the loop, check the winner
variable: